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-5x^2+3x=100+3x
We move all terms to the left:
-5x^2+3x-(100+3x)=0
We add all the numbers together, and all the variables
-5x^2+3x-(3x+100)=0
We get rid of parentheses
-5x^2+3x-3x-100=0
We add all the numbers together, and all the variables
-5x^2-100=0
a = -5; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·(-5)·(-100)
Δ = -2000
Delta is less than zero, so there is no solution for the equation
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